這個代碼有兩個問題。最大的一個問題是您有SQL注入。這就是您收到錯誤消息的原因。 永遠不要將變量直接注入SQL。這將破壞SQL并導致錯誤，甚至可能被攻擊者濫用。當您通過按按鈕提交表單時，按鈕的值被發送到PHP。然后將該值注入SQL。 // The value comes from <input name ='deposit' type='submit' value='deposit'>$deposit = $_POST['deposit'];$sql = "UPDATE bank SET bank = bank + $deposit, cash_on_hand = cash_on_hand - $deposit WHERE id=1";// this becomes an invalid query$sql = "UPDATE bank SET bank = bank + deposit, cash_on_hand = cash_on_hand - deposit WHERE id=1"; 始終將準備好的語句與參數綁定一起使用。 include 'db.php';if (isset($_POST['deposit'])) { $deposit = $_POST['deposit']; $stmt = $conn->prepare('UPDATE bank SET

你想做什么手術？這里還有一個黑客用單引號將要傳遞給mysql服務器的字符串括起來；例如： $name = "my name"$query = " INSERT INTO mytable VALUES ( 1 , '$name') "

您無法計算別名本身，因此查詢的第一行就是導致錯誤的原因： SELECT COUNT(r) 要解決這個問題，可以使用COUNT(*)： SELECT COUNT(*) 或者，您可以計算smart_calculator_result表中的實際列，例如。 SELECT COUNT(r.idSmartCalculatorResult)

您在遷移過程中丟失了它，請添加 $schema->string('description')->nullable() 在數據庫遷移文件中，位于database/migrations/<date\u and\u table\u name>。php并再次運行php artisan migrate:refresh或等效的數據庫遷移命令。

mysql不支持完全連接，但oracle支持您可以使用selectcustomers.CompanyName、orders.OrderID從客戶、訂單中customers.CustomerID=orders.CustomerID按customers.CompanyName排序；

你在嘗試這樣的事情嗎： CREATE TABLE OCCUPATIONS ( Occupation varchar(100) );INSERT INTO OCCUPATIONS VALUES ('doctor'),('doctor'), ('singer'),('singer'), ('doctor'),('doctor'), ('singer'),('singer'), ('doctor'),('singer'), ('singer'),('singer');SELECT CASE WHEN Occupation = "doctor" THEN CONCAT("There are a total of ", tbl.dCount, " " , Occupation, "s.") WHEN Occupation = "singer" THEN CONCAT("There are a total of ", tbl.sCount, " " , Occupation, "s.") END as total_countFROM ( SELECT COUNT(Occupation) AS dCount,null as sCount, Lower(Occupation) AS Occupation FROM OCCUPATIONS WHERE Occupation = 'doctor'gro

在子查詢中，您將dogs.dog_guid別名為dogID，因此您也應該在外部查詢中引用dogID。 SELECT cleaned.dogID, cleaned.dimension, AVG(cleaned.numtests) AS AvgtestsFROM( SELECT d.dog_guid AS dogID, d.dimension, COUNT(c.created_at) AS numtests FROM dogs d INNER JOIN complete_tests c ON d.dog_guid = c.dog_guid GROUP BY dogID) AS cleanedGROUP BY cleaned.dogID, cleaned.dimension;

您需要添加@JoinColumn注釋，以指定TimesheetDay實體中的列名值。 @ManyToOne@JoinColumn(name="timesheetid")private Timesheet timesheet;

缺少了用來告訴MySQL它是字符串值而不是cloumn的引號。 $"INSERT INTO ValidationStatuses(Id,Name) VALUES('{(int) ValidationStatusEnum.ValidationRequired}','{ValidationStatusEnum.ValidationRequired})'"); 您可能需要將我在MySQL中添加的單引號替換為雙引號。

在關系中使用模型名為SvDiscount::class時，laravel將從類名推斷外鍵。 For example: Class product { public function discount() { return $this->belongsTo(SvDiscount::class); }} 在代碼中使用此關系時，laravel將推斷products表中的外鍵名為sv_discount_id。 一個簡單的解決辦法是將這些字段重命名為sv_discount_id。 另一種解決方案是在關系（文檔）中指定外鍵： Class product { public function discount() { return $this->belongsTo(SvDiscount::class, 'svdiscount_id'); }}

.update(objOrAnArrayOfObjects)和.insert()是不同的SQL操作。 Insert允許一次向數據庫插入多行，因此.insert()允許向數據庫傳遞對象數組。 .update(obj)將單個值集更新為與查詢的where部分匹配的行。因此，傳遞一個對象數組對更新不起作用。

我想這對你有用。 SELECT customerTable.isActive, @Orders := (SELECT COUNT(*) FROM orderTable WHERE orderTable.customerId = customerTable.id) AS Orders, CASE WHEN @Orders > 10 THEN 'Big buyer' WHEN @Orders > 12 THEN 'Biggest buyer' END AS 'Type'FROM customerTable; 列列表中的SELECT被認為是一個子查詢。

在觸發器中，您試圖更新利潤表，但您引用了brands表(brands.brandId和{brands.viewsCounte401}）中的列，而沒有加入該表。 我不能完全確定您使用的是哪個版本的sql，但觸發器的UPDATE語句需要與brands表連接；類似這樣： UPDATE profitsSET moneyReceived = moneyReceived+1, profitDate=GETDATE()FROM profitsJOIN brands ON profits.brandId_profits = brands.brandidWHERE (brands.brandId = brandId_profits) and (brands.viewsCounter % 5 = 0); 更新：抱歉-看起來您可能正在使用mysql？ 下面是mysql的UPDATE with JOIN語句。。。 UPDATE profitsJOIN brands ON brandId = brandId_profitsSET moneyReceived = moneyReceived+1, profitDate=now()WHERE (brands.brandId = brandId_profits) AND (brands.viewsCounter % 5 = 0);

您的配置應如下所示： ... //Communities builder.Entity<Community>(entity => { builder.ToTable("Community"); builder.HasKey(c => c.Id); builder.Property(c => c.Id).HasColumnName("CommunityId").ValueGeneratedOnAdd(); entity.Property(c => c.Name).IsRequired(); entity.Property(c => c.FrontId).IsRequired(); // entity.Property(c => c.Ranks).IsRequired(false); entity.HasMany(c => c.Ranks).WithOne().HasForeignKey(c => c.CommunityId).IsRequired(); }); //Ranks builder.Entity<Rank>(entity => { builder.ToTable("Rank"); builder.HasKey(r => r.Id); builder.Property(r => r.Id

`people.addressId`上的反勾號應為`people`.`addressId`。`addresses`.`addressId`也是如此。 沒有必要在SELECT節上添加括號[()]，所以SELECT (:a,:b,:c,:d, `people.addressId` , `personId` , `lName` ,`fName`)應該是SELECT :a,:b,:c,:d, `people`.`addressId` , `personId` , `lName` ,`fName` 因此，更新后的代碼應為： $incomeMonthly = $_POST['incomeMonthly'];$isIncomeSourceSalary = $_POST['isIncomeSourceSalary'];$isIncomeSourceBusiness = $_POST['isIncomeSourceBusiness'];$isIncomeSourceRemittance = $_POST['isIncomeSourceRemittance'];$sql = "INSERT INTO `households` (`incomeMonthly`, `isIncomeSourceBusiness`, `isIncomeSourceSalary`,`isIncomeSourceRemitt