這里發(fā)生了一些事情。第4行有效而第3行無效的原因是您只檢查一次以“\”結(jié)尾的行。由于第三行有多個(gè)斜杠，所以仍在拆分。這可以通過將“\”檢查從“if”更改為“while”來解決 def get_lines(path):output=''filehandle = open(path, 'r')lines = filehandle.readline()for lines in filehandle: if lines.startswith('#'): continue else: while lines.rstrip().endswith('\\'): next_line = next(filehandle) lines = lines.rstrip()[:-1] + next_line output += lines output = lines.split("#",1) lines = output[0] yield linesa = (get_lines('C:\\Users\Swayam\Documents\ok2.txt'))[print(x) for x in a] 此代碼生成： <line0><line1><line2><line3.1 line3.2 line3.3><line4.1 line4.2> 雖然這是一

Input : tweet_id airline sentiment \0 0 570306133677760513 neutral 1 1 570301130888122368 positive 2 2 570301083672813571 neutral text Raiting \0 @VirginAmerica What @dhepburn said 2 1 @VirginAmerica plus youve added commercials 3 2 @VirginAmerica I didn't today 0 # Using regex, removing words starting with @dframe["text_corrected"] = dframe.text.str.replace("@\w+\s", "") Output : tweet_id airline sentiment \0 0 570306133677760513 neutral 1 1 570301130888122368 positive 2 2 570301083672813571 neutral text Raiting \0 @VirginAmerica What @dhepburn said 2 1 @VirginAmerica plus youve added commerc

您只需在列表中連接，并使用所需元素的len進(jìn)行篩選 >>> [[i+j] for i, j, *_ in list_of_lists if len(i)==6 and len(j)==4][['9120000068'], ['9568118334'], ['9567183693'], ['9567230486']]

你可能是說： df.to_excel(r'C:\OUTPUT\SALES_'+ MONTH.item() + '_' + YEAR.item() + '.xlsx', index=False ) Or: df.to_excel(r'C:\OUTPUT\SALES_'+ MONTH[0] + '_' + YEAR[0] + '.xlsx', index=False )

不知道我是否正確理解你。但我想你想只對(duì)字母排序而不改變non-letters嗎？ 以下是我的方法： const Reverser = (str) => { // create sorted array of all letters found // first remove all non-letters, then split into array // then sort in reverse so that we can use fast .pop() instead of slow .shift() let letters = str.replace(/[^a-zA-Z]+/gm, '').split('').sort().reverse(); // find letters and replace them with those in array, one by one return str.replace(/[a-zA-Z]/gm, () => { return letters.pop(); });}console.log(Reverser('z<*zj')); // j<*zzconsole.log(Reverser('xy-a=cb')); // ab-c=xy

您好，這段代碼運(yùn)行良好； public static void main(String[] args) { String a = "ABC"; String b = "BCD"; String c = "CDE"; String result = ""; result = parseSpecialString(a, b, c); System.out.println(result);}/** * @param strArr is any size str arguments * @return example : A, B, C B, C, D C, D, E */static String parseSpecialString(String ...strArr){ StringBuilder sb = new StringBuilder(); String NEW_LINE = "\n"; for (String str : strArr) { sb.append(convertCsvStr(str)).append(NEW_LINE); } return sb.toString();}//convert ABC -> A, B, Cstatic String convertCsvStr(String str){ StringBuilder sb = new StringB

Try running: t=eval("\""+t+"\"") 轉(zhuǎn)換它。

要從int中獲取相應(yīng)的字符，請(qǐng)使用built-inchr函數(shù)： >>> chr(101)'e'>>> chr(0x1F600)'😀' 然而，你似乎想迭代所有小寫字母。string模塊中的常量ascii_lowercase更適合于此目的。 import stringdct = {} # don't use 'dict' as a variable name, it shadows the dict constructorfor c in string.ascii_lowercase: dct[c] = ''

從列中刪除字母可能有效： gsub('[a-z]','',data$yearmonthweek)

我已經(jīng)解決了這個(gè)問題，我猜await沒有返回任何內(nèi)容，因此沒有執(zhí)行下面的行（甚至是print行）。我已經(jīng)在app.run中將host設(shè)置為0.0.0.0，并在flutter應(yīng)用程序中使用ipv4地址，一切都開始工作。在python：app.run(debug=True,host='0.0.0.0', port=5000)的Flutter中（url是：http://192.168.1.2:5000/tt

我們可以使用stringdist library(fuzzyjoin)stringdist_inner_join(df1, df2, by = 'book')

\p{Print}是\p{XPosixPrint}的別名。 /(?!')\p{Print}/ # Worst performance and kinda yuck? /\p{Print}(?<!')/ # Better performance but yuckier? /[^\P{Print}']/ # Best performance, but hard to parse.[1] use experimental qw( regex_sets ); # No idea why still experimental./(?[ \p{Print} - ['] ])/ # Best performance and clearest. char that is (printable and not(')) = char that is (not(not(printable and not(')))) = char that is (not(not(printable) or not(not(')))) = char that is (not(not(printable) or ')) = [^\P{Print}']

也許是這樣的： for(col in intersect(colnames(mat1), colnames(mat2))) { mat2[,col] <- mat1[,col]}

連接時(shí)需要將\添加到路徑： read_this_file = '\\folder1\\folder2\\' + max(filename_list) 但避免這個(gè)問題的更好方法是使用 os.path.join("\\folder1\\folder2", max(filename_list))

const chars = {0: "R",1: "E",2: "G",3: "U",4: "L",5: "A",6: "R"}Object.values(chars).join('');