我有三張表。
國家:id,country_name州:id,country_id,state_name城市:id,state_id,city_name
我想得到一個(gè)特定的國家($id=1),每個(gè)州的所有城市。我試試這個(gè)代碼。
DB::table('country as a')
->join('state as b', 'b.country_id', '=', 'a.id')
->join('city as c', 'c.state_id', '=', 'b.id')
->select('a.*', 'b.*', 'c.*')
->where('a.id', '=', $id)
->get();
得到這樣的結(jié)果。
result: [
{id: 1, country_id: 1, country_name: ABC, state_name: aaa, state_id: 0, city_name: city a1},
{id: 2, country_id: 1, country_name: ABC, state_name: aaa, state_id: 0, city_name: city a2},
{id: 3, country_id: 1, country_name: ABC, state_name: aaa, state_id: 0, city_name: city a3},
{id: 4, country_id: 1, country_name: ABC, state_name: aaa, state_id: 0, city_name: city a4},
{id: 5, country_id: 1, country_name: ABC, state_name: bbb, state_id: 1, city_name: city b1},
{id: 6, country_id: 1, country_name: ABC, state_name: bbb, state_id: 1, city_name: city b2},
{id: 7, country_id: 1, country_name: ABC, state_name: bbb, state_id: 1, city_name: city b3},
{id: 8, country_id: 1, country_name: ABC, state_name: bbb, state_id: 1, city_name: city b4},
.....
]
我希望能得到這樣的結(jié)果。
result: [
{
id: 1,
country_id: 1,
country_name: ABC,
state_name: aaa,
state_id: 0,
city: [
{city_name: city a1},
{city_name: city a2},
{city_name: city a3},
{city_name: city a4}
]
},
{
id: 2,
country_id: 1,
country_name: ABC,
state_name: bbb,
state_id: 1,
city: [
{city_name: city b1},
{city_name: city b2},
{city_name: city b3},
{city_name: city b4}
]
},
.....
and like that for other states.
]
也許有人能幫我給你一個(gè)新的見解。非常感謝你。
Leveraging Eloquent Relationships
模型與關(guān)系
Query